Question 48

Mathematics Matrices Medium

If \( A=\left[\begin{array}{ll}a & b \\ b & a\end{array}\right] \) and \( A^2=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right] \) then

(A) \( \alpha=2ab, \beta=2ab \)
(B) \( \alpha=a^2+b^2, \beta=2ab \)
(C) \( \alpha=a^2+b^2, \beta=a^2-b^2 \)
(D) \( \alpha=2ab, \beta=a^2+b^2 \)
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Given the matrix: \[ A = \begin{bmatrix} a & b \\ b & a \end{bmatrix} \] We need to find \( A^2 \). Step 1: Compute \( A^2 \) \[ A^2 = A \times A = \begin{bmatrix} a & b \\ b & a \end{bmatrix} \times \begin{bmatrix} a & b \\ b & a \end{bmatrix} \] Using matrix multiplication: \[ A^2 = \begin{bmatrix} a \cdot a + b \cdot b & a \cdot b + b \cdot a \\ b \cdot a + a \cdot b & b \cdot b + a \cdot a \end{bmatrix} \] \[ A^2 = \begin{bmatrix} a^2 + b^2 & 2ab \\ 2ab & a^2 + b^2 \end{bmatrix} \] Comparing with the given form: \[ A^2 = \begin{bmatrix} \alpha & \beta \\ \beta & \alpha \end{bmatrix} \] We conclude: \[ \alpha = a^2 + b^2, \quad \beta = 2ab \] Thus, the correct option is: \[ \text{Option B: } \alpha = a^2 + b^2, \quad \beta = 2ab \]

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