In a B+ tree, If the search-key value is 8 bytes long, the block size is 512 bytes and the block pointer size is 2 bytes, then maximum order of the B+ tree is
B⁺ Tree: Internal Node Calculation
Given Data:
Disk Block Size (D) = 512 bytes
Block Pointer (B) = 2 bytes
Key Field (K) = 8 bytes
Order (p) = ?
Formula:
\[
p \times 2 + (p - 1) \times 8 \leq 512
\]
Calculation:
\[
p \times 2 + (p - 1) \times 8 \leq 512
\]
\[
2p + 8p - 8 \leq 512
\]
\[
10p - 8 \leq 512
\]
\[
10p \leq 520
\]
\[
p \leq 52
\]
Thus, the order (p) of the B⁺ Tree is 52.
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