Half of a large Pizza is cut into 4 equal-sized pieces, and the other half is cut into 6 equal-equal sized pieces. If a person were to eat 1 of the large pieces and 2 of the smaller pieces, what fraction of the pizza would remain uneaten?
Step-by-step Solution:
Step 1: Define the Pizza Fractions
The first half of the pizza is cut into 4 equal pieces, so each piece is:
\[
\frac{1}{4} \text{ of half} = \frac{1}{8} \text{ of the whole pizza}
\]
The second half of the pizza is cut into 6 equal pieces, so each piece is:
\[
\frac{1}{6} \text{ of half} = \frac{1}{12} \text{ of the whole pizza}
\]
Step 2: Calculate the Eaten Portion
The person eats:
1. 1 large piece from the first half → \( \frac{1}{8} \)
2. 2 smaller pieces from the second half → \( 2 \times \frac{1}{12} = \frac{2}{12} = \frac{1}{6} \)
Now, find the total eaten fraction:
\[
\frac{1}{8} + \frac{1}{6}
\]
Find the LCM of 8 and 6, which is 24:
\[
\frac{1}{8} = \frac{3}{24}, \quad \frac{1}{6} = \frac{4}{24}
\]
Adding them together:
\[
\frac{3}{24} + \frac{4}{24} = \frac{7}{24}
\]
Step 3: Find the Remaining Fraction
The total pizza was 1 whole (or \( \frac{24}{24} \)), so the uneaten portion is:
\[
1 - \frac{7}{24} = \frac{24}{24} - \frac{7}{24} = \frac{17}{24}
\]
Final Answer
\(
\frac{17}{24}
\)