Maximum number of different boolean function involving in n boolean variable
Step-by-step Solution:
The maximum number of different Boolean functions involving \( n \) Boolean variables is given by:
\[
2^{2^n}
\]
Explanation:
1. Each Boolean function maps every possible combination of \( n \) Boolean variables (which can be either \( 0 \) or \( 1 \)) to an output value (either \( 0 \) or \( 1 \)).
2. The number of different input combinations for \( n \) variables is:
\[
2^n
\]
since each variable can independently be either \( 0 \) or \( 1 \).
3. For each of these \( 2^n \) input combinations, the function can output either \( 0 \) or \( 1 \), meaning there are:
\[
2^{2^n}
\]
different possible Boolean functions.
Example Calculations:
- For \( n = 1 \):
\[
2^{2^1} = 2^2 = 4
\]
- For \( n = 2 \):
\[
2^{2^2} = 2^4 = 16
\]
- For \( n = 3 \):
\[
2^{2^3} = 2^8 = 256
\]
- For \( n = 4 \):
\[
2^{2^4} = 2^{16} = 65,536
\]
This function count grows exponentially as \( n \) increases.