Question 22

Mathematics Definite Integrals Hard

If \( f(a+b-x) = f(x) \) then \( \int_{b}^{a} xf(x) \,dx \) is equal to?

(A) \( \frac{b+a}{2} \int_{b}^{a} f(x) d x \)
(B) \( \frac{b-a}{2} \int_{a}^{b} f(x) d x \)
(C) \( \frac{a+b}{2} \int_{b}^{a} f(a+x) d x \)
(D) \( \frac{a+b}{2} \int_{a}^{b} x f(x) d x \)
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\[ I = \int_{b}^{a} x f(x) \,dx \quad \dots (1) \] \[ I = \int_{b}^{a} (a + b - x) f(a + b - x) \,dx \] \[ \left( \because \int_{b}^{a} f(x) \,dx = \int_{b}^{a} f(a + b - x) \,dx \right) \] \[ I = \int_{b}^{a} (a + b - x) f(x) \,dx \] \[ I = (a + b) \int_{b}^{a} f(x) \,dx - I \quad \text{[Using (1)]} \] \[ I + I = (a + b) \int_{b}^{a} f(x) \,dx \] \[ 2I = (a + b) \int_{b}^{a} f(x) \,dx \] \[ I = \frac{a + b}{2} \int_{b}^{a} f(x) \,dx \]

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