The center and radius for the circle \( x^{2}+y^{2}+6x-4y+4=0\) respectively are:
Explanation:
We are given the circle equation: \[ x^{2} + y^{2} + 6x - 4y + 4 = 0 \]
Step 1: Rearrange terms
\[ x^{2} + 6x + y^{2} - 4y + 4 = 0 \]Step 2: Complete the squares
\[ (x^{2} + 6x + 9) + (y^{2} - 4y + 4) = -4 + 9 + 4 \] \[ (x+3)^{2} + (y-2)^{2} = 9 \]Step 3: Identify center and radius
✅ Correct option is: (D) (-3, 2) and 3
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