Question:

Consider the following alphabet series: $$ ABCDEFGHIJKLMNOPQRSTUVWXYZ $$ If the second half of the given alphabet series is written in reverse order, which letter will be seventh to the right of the twelfth letter from the left end?

Solution:

Step 1: Write the alphabet series

Original sequence: $$ A \ B \ C \ D \ E \ F \ G \ H \ I \ J \ K \ L \ M \ N \ O \ P \ Q \ R \ S \ T \ U \ V \ W \ X \ Y \ Z $$

Step 2: Divide into two halves

First half (13 letters): $$ A \ B \ C \ D \ E \ F \ G \ H \ I \ J \ K \ L \ M $$ Second half (13 letters): $$ N \ O \ P \ Q \ R \ S \ T \ U \ V \ W \ X \ Y \ Z $$

Step 3: Reverse the second half

Reversed second half: $$ Z \ Y \ X \ W \ V \ U \ T \ S \ R \ Q \ P \ O \ N $$

Step 4: Construct the new sequence

New sequence: $$ A \ B \ C \ D \ E \ F \ G \ H \ I \ J \ K \ L \ M \ Z \ Y \ X \ W \ V \ U \ T \ S \ R \ Q \ P \ O \ N $$

Step 5: Find the 12th letter from the left

The 12th letter is: $$ L $$

Step 6: Move 7 letters to the right

Counting from \(L\): \(L \rightarrow M(13), Z(14), Y(15), X(16), W(17), V(18), U(19)\) The 7th letter is: $$ U $$

Final Answer:

Option (C) : U