Question 38

Computer Awareness Boolean algebra Easy

Match List-I with List-II. $$\begin{array}{|c|l|} \hline \textbf{List-I (JK Flip Flop inputs)} & \textbf{List-II (Next State)} \\ \hline (A)\ 0\ 0 & (I)\ Toggle \\ \hline (B)\ 0\ 1 & (II)\ Set \\ \hline (C)\ 1\ 0 & (III)\ Reset \\ \hline (D)\ 1\ 1 & (IV)\ No\ Change \\ \hline \end{array}$$

(A) (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
(B) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(C) (A)-(IV), (B)-(II), (C)-(I), (D)-(III)
(D) (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
View Dynamic Solution & Explanation
Correct Solution: Option B

Step-by-step Solution:

Solution:

We are asked to match the inputs of a JK Flip-Flop with its corresponding next states. Recall the characteristic table of a JK Flip-Flop:

$$\begin{array}{|c|c|c|} \hline J & K & \text{Next State (Q\_{n+1})} \\ \hline 0 & 0 & \text{No Change} \\ \hline 0 & 1 & \text{Reset (0)} \\ \hline 1 & 0 & \text{Set (1)} \\ \hline 1 & 1 & \text{Toggle (Complement)} \\ \hline \end{array}$$

Now match each case:

  • (A) 0 0 → (IV) No Change
  • (B) 0 1 → (III) Reset
  • (C) 1 0 → (II) Set
  • (D) 1 1 → (I) Toggle

✅ Correct Answer: (A)-(IV), (B)-(III), (C)-(II), (D)-(I)Option B