Question 15

Mathematics Trigonometric Equations Hard

The value of tan 1° tan 2° tan 3° ... tan 89° is:

(A) 0
(B) <span class="math-tex">\(\frac{1}{\sqrt{2}}\)</span>
(C) 1
(D) 2
✓ Correct Answer: Option C Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

1. Pairing Tangent Values: Notice that \( \tan(90^\circ - \theta) = \cot \theta \). Therefore, we can pair the terms as follows: \[ \tan 1^\circ \tan 89^\circ = \tan 1^\circ \cot 1^\circ = \tan 1^\circ \cdot \frac{1}{\tan 1^\circ} = 1 \] \[ \tan 2^\circ \tan 88^\circ = \tan 2^\circ \cot 2^\circ = \tan 2^\circ \cdot \frac{1}{\tan 2^\circ} = 1 \] \[ \vdots \] \[ \tan 44^\circ \tan 46^\circ = \tan 44^\circ \cot 44^\circ = \tan 44^\circ \cdot \frac{1}{\tan 44^\circ} = 1 \] 2. Middle Term: The middle term is \( \tan 45^\circ \), which is: \[ \tan 45^\circ = 1 \] 3. Calculate the Product: Since each pair multiplies to 1 and the middle term is also 1, the entire product is: \[ \tan 1^\circ \tan 2^\circ \tan 3^\circ \ldots \tan 89^\circ = 1 \] Therefore, the value of the product is: \[ \boxed{1} \]

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