The result of multiplication of the numbers (10101)<sub>2</sub> and (11101)<sub>2</sub> in hexadecimal form is
\(10101_2 = 21\) and \(11101_2 = 29\). So \(21 \times 29 = 609\).
\(609 = 2 \times 256 + 6 \times 16 + 1\), which is \(261_{16}\).
Answer: (C) 261
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