ax x, logbx x and..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> ax x, logbx x and..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> ax x, logbx x and..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />
If a, b, c are in geometric progression, then log<sub>ax</sub> x, log<sub>bx</sub> x and log<sub>cx</sub> x are in
\(\log_{ax}x = \frac{1}{\log_x(ax)} = \frac{1}{\log_x a + 1}\). The same holds for b and c.
a, b, c are in GP, so \(\log_x a, \log_x b, \log_x c\) are in AP. Adding 1 to each keeps them in AP.
The given terms are the reciprocals of an AP, so they are in harmonic progression.
Answer: (C) Harmonic progression
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