If x, y, z are three consecutive positive integers, then log (1 + xz) is
Let \(x = y - 1\) and \(z = y + 1\).
\(1 + xz = 1 + (y-1)(y+1) = 1 + y^2 - 1 = y^2\)
\(\log(1 + xz) = \log y^2 = 2\log y\)
Answer: (D)
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