Let the first tower have height H, and the second tower height h. The distance between them is 25 m.

• Angle of depression 60° to the base of the second tower: \(\tan 60° = \frac{H}{25}\), so \(H = 25\sqrt{3}\).
• Angle of depression 30° to the top of the second tower: \(\tan 30° = \frac{H - h}{25}\), so \(H - h = \frac{25}{\sqrt{3}}\).

\(h = 25\sqrt{3} - \frac{25}{\sqrt{3}} = \frac{75 - 25}{\sqrt{3}} = \frac{50}{\sqrt{3}}\) m

Answer: (A)