The minimum number of NAND gates required to realize AB + AB'C + AB'C' is
Simplify: \(AB + AB'C + AB'C' = AB + AB'(C + C') = AB + AB' = A(B + B') = A\)
The output is just A, a wire. No gates are needed.
Answer: (D) 0
Reinforce your conceptual grasp with related questions from MAH MCA CET 2015:
Given f1 , f3 and f in canonical sum of products...
Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.
Start Free Mock Test Series →