Question 7

Mathematics Sequence And Series Hard

Sum to infinity of a geometric is twice the sum of first two terms. Then what are the possible values of the common ratio?

(A) <span class="math-tex">\(\pm \frac{1}{\sqrt{2}}\)</span>
(B) <span class="math-tex">\(\pm \frac{1}{2}\)</span>
(C) <span class="math-tex">\(\pm \frac{1}{\sqrt{3}}\)</span>
(D) <span class="math-tex">\(\pm \frac{1}{3}\)</span>
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\(\frac{a}{1-r} = 2(a + ar) = 2a(1 + r)\)

\(1 = 2(1 - r)(1 + r) = 2(1 - r^2) \Rightarrow r^2 = \frac{1}{2}\)

\(r = \pm\frac{1}{\sqrt{2}}\) (both satisfy \(|r| < 1\))

Answer: (A)

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