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Question 13

Mathematics Limit of Functions Hard

If (1 + x - 2x<sup>2</sup>)<sup>6</sup>&nbsp;= 1&nbsp;+ a<sub>1</sub>x + a<sub>2</sub>x<sup>2</sup>&nbsp;+ ... + a<sub>12</sub>x<sup>12</sup>, then&nbsp;a<sub>2</sub>&nbsp;+ a<sub>4</sub>&nbsp;+ ... a<sub>12</sub>&nbsp;is?

(A) 29
(B) 30
(C) 31
(D) 32
✓ Correct Answer: Option C Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Let \(P(x) = (1 + x - 2x^2)^6\).

  • \(P(1) = (1 + 1 - 2)^6 = 0\), which is the sum of all coefficients.
  • \(P(-1) = (1 - 1 - 2)^6 = 64\), which is the even-power coefficients minus the odd-power ones.

Sum of even-power coefficients (including \(a_0 = 1\)) = \(\frac{P(1) + P(-1)}{2} = 32\).

\(a_2 + a_4 + \dots + a_{12} = 32 - 1 = 31\)

Answer: (C) 31

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