How many 4 - digit numbers that can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
To be divisible by 5, the last digit must be 5 (0 is not available).
The other 3 places are filled from the remaining 5 digits {2, 3, 6, 7, 9} without repetition: \(5 \times 4 \times 3 = 60\).
Answer: (B) 60
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