Question 73

Mathematics Permutation and Combination Hard

How many 4 - digit numbers that can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

(A) 216
(B) 60
(C) 24
(D) 25
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

To be divisible by 5, the last digit must be 5 (0 is not available).

The other 3 places are filled from the remaining 5 digits {2, 3, 6, 7, 9} without repetition: \(5 \times 4 \times 3 = 60\).

Answer: (B) 60

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