If N is a 16-bit signed integer, The 2’s complement representation of N is (F87B)<sub>16</sub>.The 2’s complement representation of 8*N is ________
Multiplying by 8 = an arithmetic left shift by 3 bits.
\(F87B_{16} = 1111\,1000\,0111\,1011\). Shifted left by 3: \(1100\,0011\,1101\,1000 = C3D8_{16}\).
Check: N = −1925 and 8N = −15400, which fits in 16 bits, so there is no overflow. \(C3D8_{16}\) represents −15400.
Answer: (A) \(C3D8_{16}\)
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