If n is an integer between 0 to 21, then find a value of n for which the value of \(n!(21-n)!\) is minimum
\(n!(21 - n)! = \frac{21!}{\binom{21}{n}}\). This is smallest when \(\binom{21}{n}\) is largest.
For odd N = 21, the largest binomial coefficients are at the middle terms, n = 10 or 11.
Among the options, n = 10.
Answer: (B) 10
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