Question 4

Mathematics Tangents and Normals Hard

The number of common tangents to the circle \(x^2+y^2=4\) and \(x^2+y^2-6x-8y=24\) is

(A) 0
(B) 1
(C) 3
(D) 4
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Centre and radius of the first circle are (0, 0) and 2. Centre and radius of the second circle are (3, 4) and 5. Both the circle touch internally, hence there will be only one common tangent.

Practice Similar Tangents and Normals Questions

Reinforce your conceptual grasp with related questions from MAH MCA CET 2021:

Q1 The area of the region bounded by the \(x\)-axis and the curves defined by...
Solve →
Q2 If \(log (1-x+x 2)= a 1x+ a 2 x 2+ a 3 x 3+. . \) then \( a 3+ a 6+ a 9+....
Solve →
Q3 \(lim x ∞ (x+7/x+2) x+5 \) equal to
Solve →
Q5 In a ΔABC, if \(tan 2A/2+tan 2B/2+tan 2C/2=k\) , then k is always
Solve →
Q6 Let \( a =2 i \, + j \, +2 k \) , \( b = i - j +2 k \) and \( c = i + j -2...
Solve →
Full-Length Test Series

Prepare for MAH MCA CET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →