A cone of base radius 1 and height 15 m then which malted formed a 30 sphere of equal radius then find radius nearer to
Volume of the cone = \(\frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (1)^2 (15) = 5\pi\)
It is melted into 30 equal spheres: \(30 \times \frac{4}{3}\pi R^3 = 5\pi \Rightarrow 40 R^3 = 5 \Rightarrow R^3 = \frac{1}{8}\)
\(R = 0.5\)
Answer: (A) 0.5
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