Rohit and Tina are standing at two ends of a room with a width of 30 m . They start walking towards each other along the width of the room with a speed of \( 2 \mathrm{~m} / \mathrm{s} \) and \( 1 \mathrm{~m} / \mathrm{s} \) , respectively. Find the total distance travelled by Rohit when he meets Tina for the third time.
Step-by-step Solution:
The most efficient way to solve this problem is to first find the total distance covered by both people combined, and then use the ratio of their speeds to find Rohit's individual distance.
30 m.2 * 30 = 60 m.2 * 30 = 60 m.Therefore, the total distance covered by both until the third meeting is: 30 + 60 + 60 = 150 m.
Since they walk for the same amount of time, the distance each person covers is directly proportional to their speed.
Ratio of Speeds (Rohit : Tina) = 2 m/s : 1 m/s = 2 : 1 This means for every 3 meters they cover combined, Rohit covers 2 meters. So, Rohit will always cover 2/3 of the total combined distance.
We take Rohit's share (2/3) of the total combined distance (150 m).
Rohit's Distance = (2 / 3) * 150 m = 100 m Final Answer: The total distance travelled by Rohit when he meets Tina for the third time is 100 m.