Question 8

Mathematics Probability Easy

In a tuition batch of two students, the probability that X will pass the exam is \( \frac{2}{5} \) and that of Y is \( \frac{3}{4} \). What is the probability that neither of X and Y will pass the exam? Assume that the outcomes of exams for X and Y are independent of each other.

(A) \( \frac{3}{10} \)
(B) \( \frac{3}{20} \)
(C) \( \frac{1}{5} \)
(D) \( \frac{1}{10} \)
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Let \( P(X) \) and \( P(Y) \) be the probabilities that X and Y pass, respectively. \[ P(X) = \frac{2}{5} \] \[ P(Y) = \frac{3}{4} \] The probability that X fails is: \[ P(\neg X) = 1 - \frac{2}{5} = \frac{3}{5} \] The probability that Y fails is: \[ P(\neg Y) = 1 - \frac{3}{4} = \frac{1}{4} \] Since the events are independent, the probability that neither passes is the product of their individual probabilities of failing: \[ P(\neg X \cap \neg Y) = P(\neg X) \times P(\neg Y) \] \[ P(\neg X \cap \neg Y) = \frac{3}{5} \times \frac{1}{4} = \frac{3}{20} \]

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