Question 40

Mathematics Boolean algebra Medium

If \( 2^{a}=3^{b}=6^{-c} \) then \( a b+b c+c a= \)

(A) 1
(B) 2
(C) 0
(D) None
✓ Correct Answer: Option C Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Correct Option is C. Practice regular variations of this Boolean algebra concept to build speed and accuracy.

Practice Similar Boolean algebra Questions

Reinforce your conceptual grasp with related questions from NIMCET 2011:

Q117 Let \( x=11111010 \) and \( y=00001010 \) be two 8 -bit 2 's complement...
Solve →
Q1 The number of words that can be formed by using the letters of the word...
Solve →
Q2 If \( A-B=π/4 \) , then \( (1+tan A)(1-tan B) \) is equal to
Solve →
Q3 Let \( P(E) \) denote the probability of event \( E \) . Given \( P(A)=1,...
Solve →
Q4 The number of different license plates that can be formed in the format 3...
Solve →
Full-Length Test Series

Prepare for NIMCET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →