A causes B or C, but not both
F occurs only if B occurs
D occurs if B or C occurs
E occurs only if \( C \) occurs
J occurs only if E or F occurs
D causes G or H or both
H occurs if E occurs
\( G \) occurs if \( F \) occurs
If \( J \) occurs, which must have occurred ?
Step-by-step Solution:
To solve the syllogism, we need to trace back the conditions that must be true for J to occur.
J occurs only if E or F occurs. This means if J happens, we know for certain that either E or F (or both) must have happened first.
E occurs only if C occurs. So, if we know E happened, we also know C must have happened.
F occurs only if B occurs. So, if we know F happened, we also know B must have happened.
A causes B or C, but not both. This sets up the initial chain of events.
Since we know J occurred, we have two possible paths that could have led to it:
J occurred because E occurred. Since E only occurs if C occurs, this path requires that C must have occurred.
J occurred because F occurred. Since F only occurs if B occurs, this path requires that B must have occurred.
Therefore, for J to have occurred, one of these two paths must have been taken. This means that either B or C must have occurred.
The final answer is: B or C