Six boys \( A, B, C, D, E \) and \( F \) are marching in a line. They are arranged according to their heights, the tallest being at the back and the shortest in the front. \( F \) is between B and \( A \) . \( E \) is shorter than D but taller than \( C \) who is taller than \( A \) . \( E \) and \( F \) have two boys between them A is not the shortest among them. Where is \( E \) ?
Step-by-step Solution:
To solve this puzzle, we need to combine all the clues to create a single height ranking of the six boys from shortest to tallest. Let's use the `>` symbol to mean "is taller than".
D > E > C) and "C who is taller than A" (C > A). Combining these gives a direct chain of four boys: D > E > C > A. D > E > C > A > F > B
The question asks "Where is E?". We need to describe his position relative to the others based on our final ranking:
... D > E > C ...
This shows that E is shorter than D but taller than C.
Final Answer: E is Between D and C.