If \(I_{1}=\int_{0}^{1} 2^{x^{2}} d x, I_{2}=\int_{0}^{1} 2^{x^{3}} d x, I_{3}=\int_{1}^{2} 2^{x^{2}} d x\) and \(I_{4}=\int_{1}^{2} 2^{x^{3}} d x\), then
When \(0 < x < 1,2^{x^{3}} < 2^{x^{2}}\), hence \(\mathrm{I}_{2} < \mathrm{I}_{1}\). Again when \(1 < x < 2,2^{x^{3}}>2^{x^{2}}\), thus \(\mathrm{I}_{4}>\mathrm{I}_{3}\). \[\] Choice (D)\[\]
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