Coefficients of quadratic equation \(a x^{2}+b x+c=0\) are chosen by tossing three fair coins where 'head' means one and 'tail' means two. Then the probability that roots of the equation are imaginary is
Total number of cases is 8. \[\] \(a, b, c\) can take values 1 and 2 only. The roots are real when \(b=2, a\) and \(c\) are 1,1 . \[\] Required probability \(=1-\frac{1}{8}=\frac{7}{8}\). \[\] Choice (A)
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