Question 23

Mathematics Binomial Theorem Medium

The sum of \({ }^{20} C_{8}+{ }^{20} C_{9}+{ }^{21} C_{10}+{ }^{22} C_{11}-{ }^{23} C_{11}\) is

(A) \({ }^{22} C_{12}\)
(B) \({ }^{23} C_{12}\)
(C) 0
(D) \({ }^{21} C_{10}\)
✓ Correct Answer: Option C Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Using this formula \({ }^{n} C_{r}+{ }^{n} C_{r-1}={ }^{n+1} C_{r}\) \[\] \({ }^{20} C_{8}+{ }^{20} C_{9}+{ }^{21} C_{10}+{ }^{22} C_{11}-{ }^{23} C_{11}\) \[\] \({ }^{21} C_{9}+{ }^{21} C_{10}+{ }^{22} C_{11}-{ }^{23} C_{23}\) \[\] \({ }^{22} C_{10}+{ }^{22} C_{11}-{ }^{23} C_{11}\) \[\] \({ }^{23} C_{11}-{ }^{23} C_{11}=0\) \[\] Choice (C)

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