If \(\theta(0 \leq \theta \leq \pi)\) is the angle between the vectors \(\bar{a}\) and \(\bar{b}\), then \(\frac{|\bar{a} \times \bar{b}|}{\bar{a} \cdot \bar{b}}\) equals
We know that \(\frac{|\vec{a} \times \vec{b}|}{\vec{a} \bullet \vec{b}}=\frac{|\vec{a}||\vec{b}| \sin \theta}{|\vec{a}||\vec{b}| \cos \theta}=\tan \theta\) Choice (B)
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