Suppose the third vertex is \((x, y)\), then according to the given condition \[\] \(\frac{x+4-9}{3}=1\) and \(\frac{y-3+7}{3}=4\) \[\] \(\Rightarrow x, y=(8,8)\) \[\] Hence area of the triangle is \[\] \(\frac{1}{2}[4 \times 7+(-9 \times 8)+(8 \times-3)-(-9 \times-3)-8 \times 7-4 \times 8]\) \[\] \(=\frac{183}{2}\). \[\] Choice (C)\[\]