\(x 2 + y 2 +2gx + 2fy =..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> \(x 2 + y 2 +2gx + 2fy =..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> \(x 2 + y 2 +2gx + 2fy =..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 37

Mathematics Circle Hard

If two circles&nbsp;<span class="math-tex">\(x^2 + y^2 +2gx + 2fy = 0\)</span>&nbsp;and&nbsp;<span class="math-tex">\(x^2 + y^2 +2g's + 2f'y = 0\)</span>&nbsp;touch each other then which&nbsp;of the following is true?

(A) gf = g&rsquo;f&rsquo;
(B) g&rsquo;f = gf&rsquo;
(C) gg&rsquo; = ff&rsquo;
(D) None of these
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Both circles pass through the origin (there is no constant term). If they touch, they must touch at the origin and share the same tangent line there.

The tangent at the origin to \(x^2 + y^2 + 2gx + 2fy = 0\) is \(gx + fy = 0\). For the other circle it is \(g'x + f'y = 0\).

Same line means \(\frac{g}{g'} = \frac{f}{f'}\), that is, \(g'f = gf'\).

Answer: (B)

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