if the angles of a triangle are in the ratio 2 : 3 : 7, then the ratio of the sides opposite to these angles is
(A) <span class="math-tex">\(\sqrt{2} : 2 : \sqrt{3} + 1\)</span>
(B) <span class="math-tex">\(2 : \sqrt{2} : \sqrt{3} + 1\)</span>
(C) <span class="math-tex">\(2 : \sqrt{2} : \dfrac{\sqrt{2}}{\sqrt{3}-1}\)</span>
(D) <span class="math-tex">\(\dfrac{1}{\sqrt{2}} : 2 : \dfrac{\sqrt{3}+1}{2}\)</span>