The number of one-to-one functions from {1, 2, 3} to {1, 2, 3, 4, 5} is
Step-by-step Solution:
Let:
Domain size = 3 elements
Codomain size = 5 elements
To create a one-to-one (injective) function, every element in the domain must map to a distinct element in the codomain.
The number of such functions is given by the number of injective mappings:
\[
^5P_3 = \frac{5!}{(5 - 3)!} = \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} = 60
\]