Question 2

Mathematics Scalar and Vector Products Hard

If C is the midpoint of AB and P in any point outside AB, then

(A) <span class="math-tex">\(\overline{PA}+\overline{PB}=2\overline{PC}\)</span>
(B) <span class="math-tex">\(\overline{PA}+\overline{PB}=\overline{PC}\)</span>
(C) <span class="math-tex">\(\overline{PA}+\overline{PB}=2\overline{PC}=0\)</span>
(D) <span class="math-tex">\(\overline{PA}+\overline{PB}=\overline{PC}=0\)</span>
View Dynamic Solution & Explanation
Correct Solution: Option A

Step-by-step Solution:

Here is the MathJax representation of your given vector equations: \[ \overrightarrow{PA} = \overrightarrow{PC} + \overrightarrow{CA} \] \[ \overrightarrow{PB} = \overrightarrow{PC} + \overrightarrow{CB} \] \[ \overrightarrow{PA} + \overrightarrow{PB} = 2\overrightarrow{PC} + (\overrightarrow{CA} + \overrightarrow{CB}) \] \[ = 2\overrightarrow{PC} \quad (\because \overrightarrow{CA} = -\overrightarrow{CB}) \] \[ \text{Hence } \overrightarrow{CA} + \overrightarrow{CB} = 0 \] \[ \text{and } \overrightarrow{PA} + \overrightarrow{PB} = 2\overrightarrow{PC} \]