A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30°.
Calculation of the Height of the Pole \[\] Let AB be the vertical pole and CA be the rope. Given: \[\] ∠ACB = 30° \[\] AC = 20 m \[\] In the right-angled triangle ΔABC: \[ \sin 30° = \frac{AB}{AC} \] \[ \frac{1}{2} = \frac{AB}{20} \] \[ AB = \frac{20}{2} = 10 \text{ m} \] Thus, the height of the pole (AB) is 10 meters.
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