x 2 log2x 2 = log4x 2 is" - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> x 2 log2x 2 = log4x 2 is" - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> x 2 log2x 2 = log4x 2 is" - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 5

Mathematics Function and Relation Hard

The solution set of equation log<sub>x</sub> 2 log<sub>2x</sub> 2 = log<sub>4x</sub> 2 is

(A) <span class="math-tex">\({2^{-\sqrt{2}}, 2^{\sqrt{2}}}\)</span>
(B) <span class="math-tex">\(\left\lbrace \dfrac{1}{2}, 2 \right\rbrace\)</span>
(C) <span class="math-tex">\(\left\lbrace \dfrac{1}{4}, 2^2 \right\rbrace\)</span>
(D) <span class="math-tex">\(\left\lbrace \dfrac{1}{4}, 2 \right\rbrace\)</span>
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\[ \log_x 2 \log_{2x} 2 = \log_{4x} 2 \] \[ \therefore \log_x 2 = \frac{1}{\log_{2x} x}, \quad \log_{2x} 2 = \frac{1}{\log_{2x} x}, \quad \text{and} \quad \log_{4x} 2 = \frac{1}{\log_{4x} x} \] \[ \Rightarrow \frac{1}{\log_x 2} * \frac{1}{\log_{2x} x} = \frac{1}{\log_{4x} x} \] \[ \Rightarrow \log_x 2 \log_{2x} x = \log_{2} 4x \] \[ \Rightarrow \log_x 2 (\log_2 2 + \log_x 2) = \log_2 4 + \log_x 2 \] \[ \text{Let } \log_x 2 = a \] \[ \Rightarrow a(1 + a) = \log_2 2^2 + a \quad (\because \log_2 2 = 1) \] \[ \Rightarrow a + a^2 = 2 + a \] \[ \Rightarrow a^2 - a - 2 = 0 \] \[ \Rightarrow a = \pm \sqrt{2} \] \[ \Rightarrow \log_x 2 = \pm \sqrt{2} \] \[ \Rightarrow x = 2^{\sqrt{2}}, 2^{-\sqrt{2}} \]

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