Step-by-step Solution:

Quick Solution

The question asks which player cannot be included in a valid team of six. The most direct way to solve this is to test the inclusion of the player mentioned in the correct option (H) and show why it's impossible to form a team of 6 with them.

Analyzing the Case for Including Player H

Let's assume we try to build a team of 6 that includes H and see if it's possible by following the rules.

1. If H is IN...
   
2. ...then according to Rule 7 ("D and H cannot be members of the same team"), D must be OUT.
   
3. ...then according to Rule 8 ("The team must include both A and D or neither of them"), since D is out, A must also be OUT.
   

So, simply by including H, we are immediately forced to exclude both A and D.
Team Status: IN = {H, ...}, OUT = {A, D, ...}

Now we must satisfy Rule 5 ("The team must include exactly one among C, G and I"). Let's test the case that gets us the biggest possible team. The best case is to add **G**.

• Add **G** to the team. (Team is now {H, G}).
  
• Rule 4 ("If it includes G, it must also include F") forces us to add **F**. (Team is now {H, G, F}).
  
• Now we need to add 3 more players to reach a size of 6. The available players left are {B, E, J}. (C and I are excluded by Rule 5).
  
• However, Rule 3 ("The team must include E or B, but not both") means we can only pick **one** from the pair {B, E}.
  
• This means we can only add at most two more players (e.g., E and J, or B and J).
  

The largest possible team we can build including H is {H, G, F, E, J}, which has only 5 members. It is therefore impossible to form a team of size 6.

Final Answer: H cannot be included in the team of size 6.