The equation \( (x - a)^3 + (x - b)^3 + (x - c)^3 \) = 0 has
Step-by-step Solution:
Concept:
Nature of roots of a cubic polynomial:
Calculations:
Given equation is (x - a)3 + (x - b)3 + (x - c)3 = 0
Consider, f(x) = (x - a)3 + (x - b)3 + (x - c)3
Differentiating both sides, we get
f'(x) = 3(x - a)2 + 3(x - b)2 + 3(x - c)2
f'(x) > 0
Hence, f is an increasing function.
To find the maximum and minimum of the function, put x = ∞ in f(x):
Now, f(∞) = ∞
f(-∞) = ∞
Here, the maximum and minimum of the function are of the same sign.
Hence, the equation (x - a)3 + (x - b)3 + (x - c)3 = 0 has one real and two imaginary roots.