Question 48

Mathematics Matrices Hard

The solution of the equation&nbsp;<span class="math-tex">\(\frac {dy}{dx} = e^{x + y} + x^2e^y\)</span>&nbsp;is

(A) <span class="math-tex">\(e^{x - y} + \frac {x^3} 3 + c\)</span>
(B) <span class="math-tex">\(e^{x} + e^{-y} + \frac {x^3} 3 = c\)</span>
(C) <span class="math-tex">\(e^{x} - e^{-y} = \frac {x^3} 3 + c\)</span>
(D) None
View Dynamic Solution & Explanation
Correct Solution: Option B

Step-by-step Solution:

\[ \frac{dy}{dx} = e^{x - y} + x^2 e^{-y} \] \[ \Rightarrow dy = \left( e^{x - y} + x^2 e^{-y} \right) dx \] \[ \Rightarrow dy = \frac{e^x + x^2}{e^y} dx \] \[ \Rightarrow e^y dy = \left( e^x + x^2 \right) dx \] \[ \Rightarrow \int e^y dy = \int (e^x + x^2) dx \] \[ \Rightarrow e^y = e^x + \frac{x^3}{3} + C \] Thus, the required solution is: \[ e^y = e^x + \frac{x^3}{3} + C \]