Question 6

Mathematics Probability Hard

The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, The P(X = 1) is?

(A) 1/32
(B) 1/16
(C) 1/8
(D) 1/4
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Concept:

The binomial distribution of a random variable X is given by,

P(X = k) = \( \rm ^nC_k p^k q^{n-k} \)

Mean = np 

Variance = npq

Calculations:

Given, the mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively,

⇒ mean = np = 4         ....(1)

⇒ variance = npq = 2    ....(2)

From equation (1) and (2), we have

⇒ q = \( \rm \dfrac 12 \)

We know, p = 1 - q 

⇒ p = \( \rm \dfrac 12 \)

From equation (1), we have

n = 8 

The binomial distribution of a random variable X is given by,

P(X = k) = \( \rm ^nC_k p^k q^{n-k} \)

⇒ P(X = 1) = \( \rm ^8C_1 p^1 q^{8-1} \)

⇒ P(X = 1) = 8. \( \rm \dfrac 12 \). \( \rm \dfrac {1}{2^7} \)

⇒ P(X = 1) = \( \rm \dfrac {1}{32} \)

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