Question 29

Mathematics Permutation and Combination Hard

A student council has 10 members. From this one President, one Vice-President, one Secretary, one Joint-Secretary and two Executive Committee members have to be elected. In how many ways this can be done?

(A) 151200
(B) 75600
(C) 37800
(D) 18900
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Step 1: Elect the 4 Office Bearers
We need to select 4 specific officers (President, Vice-President, Secretary, Joint-Secretary) from 10 members.
Since the posts are distinct, the order of selection matters (Permutation).
Ways = \({}^{10}P_4 = 10 \times 9 \times 8 \times 7 = 5040\).

Step 2: Elect the Executive Committee Members
After electing the 4 officers, we have \(10 - 4 = 6\) members remaining.
We need to select 2 members for the Executive Committee.
Since these two positions are equal (order does not matter), we use Combination.
Ways = \({}^{6}C_2 = \frac{6 \times 5}{2 \times 1} = 15\).

Step 3: Total Ways
Total ways = (Ways for Office Bearers) × (Ways for Committee Members)
Total = \(5040 \times 15 = 75600\).

Practice Similar Permutation and Combination Questions

Reinforce your conceptual grasp with related questions from NIMCET 2018:

Q27 9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3...
Solve →
Q36 The number of natural numbers which are smaller than \( 2 × 10 8 \) and...
Solve →
Q57 Let n be the number of different 5 digits numbers, divisible by 4 that can...
Solve →
Q1 What is the value of: \( 6 + log 1/4 ( 1 √(2) 1 - 1 √(2) 1 - 1 √(2) 1 - 1...
Solve →
Q2 The function \( f(x)=log (x+√(x 2 +...
Solve →
Full-Length Test Series

Prepare for NIMCET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →