Three numbers a, b and c are chosen at random (simultaneously) from among the numbers 1, 2, 3, ..., 99. The probability that a<sup>3</sup> + b<sup>3</sup> + c<sup>3</sup> - 3abc is divisible by 3, is
(A) <span class="math-tex">\(\rm\frac{3\times {^{33}C_3}+ \left(^{33}C_1\right)^3}{^{99}C_3}\)</span>
(B) <span class="math-tex">\(\rm\frac{3\times {^{33}C_3}- \left(^{33}C_1\right)^3}{^{99}C_3}\)</span>
(C) <span class="math-tex">\(\rm\frac{2\times {^{33}C_3}+ \left(^{33}C_1\right)^3}{^{99}C_3}\)</span>
(D) <span class="math-tex">\(\rm \frac{2\times {^{33}C_3}-\left(^{33}C_1\right)^3}{^{99}C_3}\)</span>