Question 7

Mathematics Sequence And Series Hard

Sum to infinity of a geometric is twice the sum of first two terms. Then what are the possible values of the common ratio?

(A) <span class="math-tex">\(\pm \frac{1}{\sqrt{2}}\)</span>
(B) <span class="math-tex">\(\pm \frac{1}{2}\)</span>
(C) <span class="math-tex">\(\pm \frac{1}{\sqrt{3}}\)</span>
(D) <span class="math-tex">\(\pm \frac{1}{3}\)</span>
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Correct Option is A. Practice regular variations of this Sequence And Series concept to build speed and accuracy.

Practice Similar Sequence And Series Questions

Reinforce your conceptual grasp with related questions from NIMCET 2018:

Q8 Suppose that m and n are fixed numbers such that the mth term...
Solve →
Q18 In an acute angled ΔABC, the least value of sec A + sec B + sec...
Solve →
Q32 If \(a 1, a 2, a 3,...,a n\) are...
Solve →
Q56 If log3 2, log3(2x- 5),...
Solve →
Q1 What is the value of: \( 6 + log 1/4 ( 1 √(2) 1 - 1 √(2) 1 - 1 √(2) 1 - 1...
Solve →
Full-Length Test Series

Prepare for NIMCET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →