2 + y2 = 16 and x2 + y2 - 2y..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> 2 + y2 = 16 and x2 + y2 - 2y..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> 2 + y2 = 16 and x2 + y2 - 2y..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />
For two circles x<sup>2</sup> + y<sup>2</sup> = 16 and x<sup>2 </sup>+ y<sup>2</sup> - 2y = 0, there is / are
Circle 1: centre (0, 0), radius 4. Circle 2: \(x^2 + (y-1)^2 = 1\), centre (0, 1), radius 1.
Distance between centres = 1, which is less than \(r_1 - r_2 = 3\). So circle 2 lies completely inside circle 1.
When one circle is inside the other without touching, there are no common tangents.
Answer: (D)
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