Question 22

Mathematics Scalar and Vector Products Hard

<span class="math-tex">\(\vec a\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\vec b\)</span>&nbsp;are non-zero non-collinear vectors such that&nbsp;<span class="math-tex">\(|\vec a| = 2, \vec a.\vec b = 1\)</span>&nbsp;and the angle between&nbsp;<span class="math-tex">\(\vec a\)</span>&nbsp;and&nbsp;&nbsp;<span class="math-tex">\(\vec b\)</span>&nbsp;is&nbsp;<span class="math-tex">\(\frac \pi 3\)</span>. If&nbsp;<span class="math-tex">\(\vec r\)</span>&nbsp;is any vector satisfying&nbsp;<span class="math-tex">\(\vec r.\vec a = 2,\;​​\vec r.\vec b = 8,\;(\vec r + 2\vec a - 10\vec b).(\vec a \times \vec b) = 6\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\vec r + 2\vec a - 10 \vec b = λ(\vec a \times \vec b),\)</span>&nbsp;then&nbsp;&lambda; =

(A) <span class="math-tex">\(\frac 1 2\)</span>
(B) 2
(C) <span class="math-tex">\(\frac 4 {\sqrt 3}\)</span>
(D) 3
View Dynamic Solution & Explanation
Correct Solution: Option B

Step-by-step Solution:

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