A computer producing factory has only two plants T<sub>1</sub> and T<sub>2</sub>. Plant T<sub>1</sub> produces 20% and plant T<sub>2</sub> produces 80% of the total computers produced. 7% of the computers produced in the factory turn out to be defective. It is known that P(computer turns out to be defective given that it is produced in plant T<sub>1</sub>) = 10 × P(computer turns out to be defective given that it is produced in plant T<sub>2</sub>). A computer produced in the factory is randomly selected and it does not turn out to be defective, then the probability that it is produced in plant T<sub>2</sub> is:
Correct Option is C. Practice regular variations of this Probability concept to build speed and accuracy.
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