In a beauty contest, half the number of experts voted for Mr. A and two third voted for Mr. B. 10 voted for both and 6 did not for either. How many experts were there in all?
This problem can be solved using an algebraic approach based on the formula for the union of two sets, also known as the Principle of Inclusion-Exclusion.
From the problem statement, we can write the following expressions:
The total number of experts is the sum of those who voted for at least one candidate plus those who voted for neither. The formula is:
T = A + B - (A ∩ B) + Neither
Now we substitute our expressions into the formula:
T = (T / 2) + ((2/3) × T) - 10 + 6
T = T/2 + 2T/3 - 4
To eliminate the fractions, we can multiply the entire equation by the common denominator, which is 6:
6T = 3T + 4T - 24
6T = 7T - 24
24 = 7T - 6T
T = 24
There were 24 experts in all.
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