Question 59

Logical Reasoning Number representations Hard

Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is

(A) 4
(B) 3
(C) 2
(D) 5
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Solving with Inequalities

To find the minimum number of families, we can translate the given statements into a system of mathematical inequalities and solve for the number of families (F).

1. Define Variables

  • Let F be the total number of families.
  • Let A be the total number of adults.
  • Let B be the total number of boys.
  • Let G be the total number of girls.
  • Let C be the total number of children (C = B + G).

2. Formulate Inequalities

From the problem statement, we derive the following inequalities:

  1. "Each family ... has at most two adults" → A ≤ 2F
  2. "no family has fewer than 3 children" → C ≥ 3F
  3. "more adults than boys" → A > B
  4. "more boys than girls" → B > G
  5. "more girls than families" → G > F

3. Combine and Solve the Inequalities

From inequalities 3, 4, and 5, we can form a chain:

A > B > G > F

Since the numbers must be integers, we can establish minimum values in terms of F:

  • Since G > F, the minimum value for G is F + 1. → G ≥ F + 1
  • Since B > G, the minimum value for B is G + 1. → B ≥ (F + 1) + 1 = F + 2
  • Since A > B, the minimum value for A is B + 1. → A ≥ (F + 2) + 1 = F + 3

Now we have two inequalities involving A and F: (1) A ≤ 2F and our derived A ≥ F + 3. We can combine them:

F + 3 ≤ A ≤ 2F

This implies: F + 3 ≤ 2F → F ≥ 3.

Next, we check this against the children inequality (2), C ≥ 3F. We know C = B + G.

C = B + G ≥ (F + 2) + (F + 1) = 2F + 3.

So, we must satisfy: 2F + 3 ≥ 3F → 3 ≥ F, or F ≤ 3.

4. Conclusion

We have derived two conditions for F: F ≥ 3 and F ≤ 3. The only integer that satisfies both is F = 3.

Therefore, the minimum possible number of families in the locality is 3.

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