Using only 2, 5, 10, 25 and 50 paise coins, the smallest number of coins required to pay exactly 78 paise, 66 paise and Rs. 1.01 to three different persons is
To find the smallest total number of coins, we need to find the minimum number of coins required to pay each of the three amounts separately. The strategy for finding the minimum number of coins for a given amount is to use the largest denomination coins as much as possible.
The available coin denominations are: 50, 25, 10, 5, and 2 paise.
We break down 78 paise using the largest coins first:
Total coins = 1 (50p) + 2 (10p) + 4 (2p) = 7 coins.
We break down 66 paise using the largest coins first:
Total coins = 1 (50p) + 1 (10p) + 3 (2p) = 5 coins.
We break down 101 paise using the largest coins first:
Total coins = 1 (50p) + 1 (25p) + 2 (10p) + 3 (2p) = 7 coins.
The smallest total number of coins is the sum of the minimum coins required for each payment:
Total = (Coins for 78p) + (Coins for 66p) + (Coins for 101p)
Total = 7 + 5 + 7 = 19
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